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1. • 
   • Jens Bruntt
   • Posted on Mon 13 Mar 2006 02:26 AM

   @Jake

   This Java Agent retrieves XML (or html) when called like this:

   http://host/path/agent?Openagent&Url={Link}

   The XML then has to be parsed in some way of course. If you look in the source at {Link} you can see anexample.

   Source:

   import lotus.domino.*;

   import java.io.PrintWriter;

   import java.io.BufferedReader;

   import java.io.IOException;

   import java.io.InputStreamReader;

   import java.net.*;

   public class JavaAgent extends AgentBase {

   PrintWriter browser;

   public void NotesMain() {

   try {

   Session session = getSession();

   AgentContext agentContext = session.getAgentContext();

   Database db = agentContext.getCurrentDatabase();

   browser = new PrintWriter( getAgentOutput(), true );

   Document doc = agentContext.getDocumentContext();

   Document docToUpdate;

   String docQuery_String_Decoded = doc.getFirstItem("Query_String").getValueString();

   String urlNoAgent = docQuery_String_Decoded.substring( 14 , docQuery_String_Decoded.length() );

   System.out.println("urlNoAgent : "+urlNoAgent);

   String UrlToConnect = urlNoAgent;

   URL url = new URL(UrlToConnect);

   URLConnection uc = url.openConnection();

   BufferedReader br = new BufferedReader(new InputStreamReader(uc.getInputStream()));

   try {

   sleep(1000);

   }

   catch (Exception e) {System.out.println("Error reading - retrieve(URL url)"); }

   String in,finalstring = "";

   while ((in=br.readLine()) != null){

   finalstring += in+"\n";

   }

   browser.println("Content-Type: text/xml");

   browser.println(finalstring);

   } catch(Exception e) {

   e.printStackTrace();

   }

   }

   }

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